Answer:
Option C
Explanation:
Given,
T=27° C=300K
R= 2 cal K-1 mol-1
Reaction for combustion of carbon monoxide is given as :
$CO(g)+\frac{1}{2}O_{2}(g)\rightarrow CO_{2}(g)$
$\therefore$ $\triangle n_{g}=1-1.5=-\frac{1}{2}$
Now, the difference between heat of combustion of carbon monoxide gas at constant pressure and at constant volume is given by
$\triangle H -\triangle U= \triangle n_{g} RT$
$\therefore$ $\triangle H -\triangle U=-\frac{1}{2}\times 2\times300=-300 cal$